Library Coq.Strings.String


Contributed by Laurent Théry (INRIA); Adapted to Coq V8 by the Coq Development Team

Require Import Arith.
Require Import Ascii.

Definition of strings

Implementation of string as list of ascii characters

Inductive string : Set :=
  | EmptyString : string
  | String : ascii -> string -> string.

Delimit Scope string_scope with string.
Local Open Scope string_scope.

Equality is decidable

Definition string_dec : forall s1 s2 : string, {s1 = s2} + {s1 <> s2}.
Defined.

Concatenation of strings


Reserved Notation "x ++ y" (right associativity, at level 60).

Fixpoint append (s1 s2 : string) : string :=
  match s1 with
  | EmptyString => s2
  | String c s1´ => String c (s1´ ++ s2)
  end

where "s1 ++ s2" := (append s1 s2) : string_scope.

Length

Fixpoint length (s : string) : nat :=
  match s with
  | EmptyString => 0
  | String c => S (length )
  end.

Nth character of a string

Fixpoint get (n : nat) (s : string) {struct s} : option ascii :=
  match s with
  | EmptyString => None
  | String c => match n with
                   | O => Some c
                   | S => get
                   end
  end.

Two lists that are identical through get are syntactically equal

Theorem get_correct :
  forall s1 s2 : string, (forall n : nat, get n s1 = get n s2) <-> s1 = s2.

The first elements of s1 ++ s2 are the ones of s1

Theorem append_correct1 :
 forall (s1 s2 : string) (n : nat),
 n < length s1 -> get n s1 = get n (s1 ++ s2).

The last elements of s1 ++ s2 are the ones of s2

Theorem append_correct2 :
 forall (s1 s2 : string) (n : nat),
 get n s2 = get (n + length s1) (s1 ++ s2).

Substrings

substring n m s returns the substring of s that starts at position n and of length m; if this does not make sense it returns ""

Fixpoint substring (n m : nat) (s : string) : string :=
  match n, m, s with
  | 0, 0, _ => EmptyString
  | 0, S , EmptyString => s
  | 0, S , String c => String c (substring 0 )
  | S , _, EmptyString => s
  | S , _, String c => substring m
  end.

The substring is included in the initial string

Theorem substring_correct1 :
 forall (s : string) (n m p : nat),
 p < m -> get p (substring n m s) = get (p + n) s.

The substring has at most m elements

Theorem substring_correct2 :
 forall (s : string) (n m p : nat), m <= p -> get p (substring n m s) = None.

Test functions

Test if s1 is a prefix of s2

Fixpoint prefix (s1 s2 : string) {struct s2} : bool :=
  match s1 with
  | EmptyString => true
  | String a s1´ =>
      match s2 with
      | EmptyString => false
      | String b s2´ =>
          match ascii_dec a b with
          | left _ => prefix s1´ s2´
          | right _ => false
          end
      end
  end.

If s1 is a prefix of s2, it is the substring of length length s1 starting at position O of s2

Theorem prefix_correct :
 forall s1 s2 : string,
 prefix s1 s2 = true <-> substring 0 (length s1) s2 = s1.

Test if, starting at position n, s1 occurs in s2; if so it returns the position

Fixpoint index (n : nat) (s1 s2 : string) : option nat :=
  match s2, n with
  | EmptyString, 0 =>
      match s1 with
      | EmptyString => Some 0
      | String a s1´ => None
      end
  | EmptyString, S => None
  | String b s2´, 0 =>
      if prefix s1 s2 then Some 0
      else
        match index 0 s1 s2´ with
        | Some n => Some (S n)
        | None => None
        end
   | String b s2´, S =>
      match index s1 s2´ with
      | Some n => Some (S n)
      | None => None
      end
  end.

Opaque prefix.

If the result of index is Some m, s1 in s2 at position m

Theorem index_correct1 :
 forall (n m : nat) (s1 s2 : string),
 index n s1 s2 = Some m -> substring m (length s1) s2 = s1.

If the result of index is Some m, s1 does not occur in s2 before m

Theorem index_correct2 :
 forall (n m : nat) (s1 s2 : string),
 index n s1 s2 = Some m ->
 forall p : nat, n <= p -> p < m -> substring p (length s1) s2 <> s1.

If the result of index is None, s1 does not occur in s2 after n

Theorem index_correct3 :
 forall (n m : nat) (s1 s2 : string),
 index n s1 s2 = None ->
 s1 <> EmptyString -> n <= m -> substring m (length s1) s2 <> s1.

Transparent prefix.

If we are searching for the Empty string and the answer is no this means that n is greater than the size of s

Theorem index_correct4 :
 forall (n : nat) (s : string),
 index n EmptyString s = None -> length s < n.

Same as index but with no optional type, we return 0 when it does not occur

Definition findex n s1 s2 :=
  match index n s1 s2 with
  | Some n => n
  | None => 0
  end.

Concrete syntax

The concrete syntax for strings in scope string_scope follows the Coq convention for strings: all ascii characters of code less than 128 are litteral to the exception of the character `double quote' which must be doubled.
Strings that involve ascii characters of code >= 128 which are not part of a valid utf8 sequence of characters are not representable using the Coq string notation (use explicitly the String constructor with the ascii codes of the characters).

Example HelloWorld := " ""Hello world!"" ".